Lesson 5 5 Ndirect Proof and Inequalities in One Triangle Retech Continued
5.5 Inequalities in One Triangle - PowerPoint PPT Presentation
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5.5 Inequalities in One Triangle
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5.5 Inequalities in One Triangle Geometry Ms. Reser Objectives: Use triangle measurements to decide which side is longest or which angle is largest. – PowerPoint PPT presentation
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Title: 5.5 Inequalities in One Triangle
1
5.5 Inequalities in One Triangle
- Geometry
- Ms. Reser
2
Objectives
- Use triangle measurements to decide which side is
longest or which angle is largest. - Use the Triangle Inequality
3
Assignment
- pp. 298-300 1-25, 34
4
Objective 1 Comparing Measurements of a Triangle
- In activity 5.5, you may have discovered a
relationship between the positions of the longest
and shortest sides of a triangle and the position
of its angles.
The diagrams illustrate Thms. 5.10 and 5.11.
5
Theorem 5.10
- If one side of a triangle is longer than another
side, then the angle opposite the longer side is
larger than the angle opposite the shorter side.
m?A gt m?C
6
Theorem 5.11
- If one ANGLE of a triangle is larger than another
ANGLE, then the SIDE opposite the larger angle is
longer than the side opposite the smaller angle.
60
40
EF gt DF
You can write the measurements of a triangle in
order from least to greatest.
7
Ex. 1 Writing Measurements in Order from Least
to Greatest
- Write the measurements of the triangles from
least to greatest. - m ?G lt m?H lt m ?J
- JH lt JG lt GH
100
45
35
8
Ex. 1 Writing Measurements in Order from Least
to Greatest
- Write the measurements of the triangles from
least to greatest. - QP lt PR lt QR
- m ?R lt m?Q lt m ?P
8
7
5
9
Paragraph Proof Theorem 5.10
- Given?AC gt AB
- Prove ?m?ABC gt m?C
- Use the Ruler Postulate to locate a point D on AC
such that DA BA. Then draw the segment BD. In
the isosceles triangle ?ABD, ?1 ? ?2. Because
m?ABC m?1m?3, it follows that m?ABC gt m?1.
Substituting m?2 for m?1 produces m?ABC gt m?2.
Because m?2 m?3 m?C, m?2 gt m?C. Finally
because m?ABC gt m?2 and m?2 gt m?C, you can
conclude that m?ABC gt m?C.
10
NOTE
- The proof of 5.10 in the slide previous uses the
fact that ?2 is an exterior angle for ?BDC, so
its measure is the sum of the measures of the two
nonadjacent interior angles. Then m?2 must be
greater than the measure of either nonadjacent
interior angle. This result is stated in Theorem
5.12
11
Theorem 5.12-Exterior Angle Inequality
- The measure of an exterior angle of a triangle is
greater than the measure of either of the two non
adjacent interior angles. - m?1 gt m?A and m?1 gt m?B
12
Ex. 2 Using Theorem 5.10
- DIRECTORS CHAIR. In the directors chair shown,
AB ? AC and BC gt AB. What can you conclude about
the angles in ?ABC?
13
Ex. 2 Using Theorem 5.10Solution
- Because AB ? AC, ?ABC is isosceles, so ?B ? ?C.
Therefore, m?B m?C. Because BCgtAB, m?A gt m?C by
Theorem 5.10. By substitution, m?A gt m?B. In
addition, you can conclude that m?A gt60, m?Blt
60, and m?C lt 60.
14
Objective 2 Using the Triangle Inequality
- Not every group of three segments can be used to
form a triangle. The lengths of the segments
must fit a certain relationship.
15
Ex. 3 Constructing a Triangle
- 2 cm, 2 cm, 5 cm
- 3 cm, 2 cm, 5 cm
- 4 cm, 2 cm, 5 cm
- Solution Try drawing triangles with the given
side lengths. Only group (c) is possible. The
sum of the first and second lengths must be
greater than the third length.
16
Ex. 3 Constructing a Triangle
- 2 cm, 2 cm, 5 cm
- 3 cm, 2 cm, 5 cm
- 4 cm, 2 cm, 5 cm
17
Theorem 5.13 Triangle Inequality
- The sum of the lengths of any two sides of a
Triangle is greater than the length of the third
side. - AB BC gt AC
- AC BC gt AB
- AB AC gt BC
18
Ex. 4 Finding Possible Side Lengths
- A triangle has one side of 10 cm and another of
14 cm. Describe the possible lengths of the
third side - SOLUTION Let x represent the length of the
third side. Using the Triangle Inequality, you
can write and solve inequalities.
- x 10 gt 14
- x gt 4
- 10 14 gt x
- 24 gt x
- ?So, the length of the third side must be greater
than 4 cm and less than 24 cm.
19
24 - homework
- Solve the inequality
- AB AC gt BC.
- (x 2) (x 3) gt 3x 2
- 2x 5 gt 3x 2
- 5 gt x 2
- 7 gt x
20
5. Geography
- AB BC gt AC
- MC CG gt MG
- 99 165 gt x
- 264 gt x
- x 99 lt 165
- x lt 66
- 66 lt x lt 264
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